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Can someone please explain to me how to find the time of collision between two balls?

A ball and a ball in a 3D box that have the same mass and are made out of air collide. The box is made of a rigid material and is 1.0m high.
Solve for the time of the collision between the two balls at an impact velocity of 0.15 m/s.
I have tried using the law of conservation of momentum but the given values I have are:
$dv_{0} = 0.15 \,\,\, \mathrm{m\cdot s^{ -1}}$
$m_{1} = 4 \,\,\,\, \mathrm{g}$
$m_{2} = 12 \,\,\,\, \mathrm{g}$
$a = 1.0\,\,\, \mathrm{m}$
$v_{1} = 0.15 \,\,\, \mathrm{m\cdot s^{ -1}}$
$v_{2} = 0.15 \,\,\, \mathrm{m\cdot s^{ -1}}$
$r_{1} = 1.0\,\,\, \mathrm{m}$
$r_{2} = 2.0\,\,\, \mathrm{m}$
$v_{1} = \frac{1}{2}at^{2}$
$v_{2} = \frac{1}{2}at^{2}$
$m_{1} = \frac{1}{2}mr^{2}$
$m_{2} = \frac{1}{2}mr^{2}$

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